Answer:
The duration of the consolidation process for the same clay is 32 min
Explanation:
for clay 1:
t1=0
H1=thickness=2 cm
for the clay 2:
t2=?
H2=2 cm
The time factor is equal to:
[tex]T=(\frac{Cv}{d^{2} })t[/tex]
where Cv is the coefficient of consolidation
[tex](\frac{Cvt}{d^{2} })_{1}= (\frac{Cvt}{d^{2} })_{2}[/tex]
if Cv is constant, we have:
[tex](\frac{t1}{(\frac{H1}{2}) ^{2} })_{1}=(\frac{t2}{H2^{2} })_{2}\\\frac{0}{(\frac{2}{2})^{2}) }=\frac{t2}{2^{2} }[/tex]
Clearing t2:
t2=32 min
