Answer:
729
Step-by-step explanation:
The given expresion is
[tex]((a^{c}b)^c + ab^c - (ab^c)^c)^c[/tex]
We substitute a=3, b=-3, and c=2.
[tex]((3^{2} \times - 3)^2+ 3 \times (- 3)^2 - (3 \times (- 3)^2)^2)^2[/tex]
We evaluate the exponents to get:
[tex]((9 \times - 3)^2+ 3 \times 9 - (3 \times 9)^2)^2[/tex]
We multiply to get:
[tex](( - 27)^2+ 3 \times 9 - (27)^2)^2[/tex]
This gives;
[tex](( 27)^2+ 27 - (27)^2)^2 = {27}^{2} [/tex]
We finally evaluate square to get
[tex] = 729[/tex]
