Answer:
[tex]x_1= \frac{1+3\sqrt{3}}{2}[/tex]
[tex]x_2= \frac{1-3\sqrt{3}}{2}[/tex]
Step-by-step explanation:
We have formula for solution of quadric equation:
[tex]x_{1,2}=\frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
In our equation b=-2, a=2 and c=13, so we have:
[tex]x_{1,2}=\frac{2+-\sqrt{4+104}}{4}[/tex]
[tex]x_{1,2}=\frac{2+-6\sqrt{3}}{4}[/tex]
[tex]x_1= \frac{1+3\sqrt{3}}{2}[/tex]
[tex]x_2= \frac{1-3\sqrt{3}}{2}[/tex]
