Answer:
the speed of the blue dot when it is 0.4m above the road is 7.92 m/s
Explanation:
If the blue dot is 0.4m above the road, then it is at exactly half of the tire diameter. Thus, the vertical component on the velocity (Vj) = 5.6 m/s and the horizontal component of the velocity(Vi) is 5.6 m/s.
V = (5.6i + 5.6j)
From vector laws, the magnitude of the vector becomes;
[tex]V =\sqrt{5.6^2 + 5.6^2} = 7.92\frac{m}{s}[/tex]
Therefore, the speed of the blue dot when it is 0.4m above the road is 7.92 m/s
