Option B:
SAS postulate or theorem can be used to prove ΔLMN ≅ ΔPMN.
Solution:
Given [tex]\triangle L M N \cong \triangle P M N[/tex].
Consider ΔLMN and ΔPMN,
LN ≅ PN (Given sides)
∠LNM ≅ ∠PNM (given angles)
MN ≅ MN (Reflexive property of sides)
Therefore, by Side-Angle-Side (SAS) congruence rule,
ΔLMN ≅ ΔPMN
Hence SAS postulate or theorem can be used to prove ΔLMN ≅ ΔPMN.
Option B is the correct answer.
