Answer:
(17/8, -1/8)
Step-by-step explanation:
[tex]\left \{ {{2x-6y=5} \atop {x+y=2}} \right.[/tex]
the bottom equation is equivalent to x = 2-y
so I switch the value of x in the top equation to x = 2-y
and it becomes 2*(2-y) - 6y = 5
equal to 4 - 2y - 6y = 5
-8y = 1
y = -1/8
then you substitute this value in the second equation
x + y = 2 becomes x + (-1/8) = 2
x = 2 + 1/8 = 16/8 + 1/8 = 17/8
