Answer:
[tex](3b-a)(4c+1)[/tex]
Step-by-step explanation:
The given expression is : (3b−a)·4c+3b−a
We can rewrite this to get: (3b−a)·4c+1*(3b-a)
There is a common factor of (3b-a)
We factor to obtain: (3b−a)·[4c+1]
Therefore the completely factored form is [tex](3b-a)(4c+1)[/tex]
