Explanation:
Given that,
(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :
[tex]V=\dfrac{W}{q}[/tex]
[tex]V=\dfrac{12}{0.0001}[/tex]
[tex]V=12\times 10^4\ Volt[/tex]
(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :
[tex]V=\dfrac{W}{q}[/tex]
[tex]V=\dfrac{24}{0.0002}[/tex]
[tex]V=12\times 10^4\ Volt[/tex]
Therefore, this is the required solution.
