Answer:
[tex]\large\boxed{x=\dfrac{17}{7}}[/tex]
Step-by-step explanation:
[tex]\text{A geometric mean of}\ x\ \text{and}\ y:\\\\\sqrt{xy}\\\\\text{Let}\ x-\text{the number}.\\\\\text{Substitute:}\\\\\sqrt{17}=\sqrt{(7)(x)}\iff17=7x\qquad\text{divide both sides by 7}\\\\\dfrac{17}{7}=\dfrac{7x}{7}\to x=\dfrac{17}{7}[/tex]
