Respuesta :

eric

[tex]\text{Welcome!}\\\\\text{Your equation should look like:}\\c = \sqrt{a^2 + b^2 - 2 \a \ b\ cos Y} \\c = \sqrt{55^2 + 50^2 - 2 * 55 * 50 * cos (90 \ degrees)\\ \\\fbox{ c = 74.33034}\checkmark[/tex]

Answer:

∠Y ≈ 32.7°

Step-by-step explanation:

Using the cosine rule in Δ XYZ

cosY = [tex]\frac{x^2+z^2-y^2}{2xz}[/tex] ← substitute values

        = [tex]\frac{90^2+50^2-55^2}{2(90)(50)}[/tex]

        = [tex]\frac{7575}{9000}[/tex], thus

Y = [tex]cos^{-1}[/tex]( [tex]\frac{7575}{9000}[/tex]) ≈ 32.7°

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