x²+6x-15=-8
x²+6x-7=0
Δ= b²-4ac = 36+28=64
x₁,₂= [tex]\frac{-6(+/-)\sqrt{64} }{2}[/tex]
x1= [tex]\frac{-6+\sqrt{64} }{2}[/tex]=[tex]\frac{-6+8 }{2}[/tex]=
[tex]\frac{2}{2}[/tex]=1
x2= [tex]\frac{-6-sqrt{64} }{2}[/tex]=[tex]\frac{-6-8 }{2}[/tex]=
[tex]\frac{-14}{2}[/tex]=7
Answer:
x²+6x-15=-8
Step-by-step explanation:
x = (1)
x²= 1
6x = 6
6 + 1 = 7
7 - 15 = -8
(Hope this helps)
