Answer:
solved
Step-by-step explanation:
[tex]log_b2= 0.3869[/tex]
[tex]log_b3= 0.6131[/tex]
[tex]log_b5= 0.8982[/tex]
we now that
[tex]log_b10= log_b(2\times5)[/tex]
[tex]log_b10= log_b2 +log_b5[/tex]
[tex]log_b10= 0.3869 +0.8982[/tex]
[tex]log_b10=1.2851[/tex]
