Answer:x=4,8
Step-by-step explanation:
Given
[tex]x=2\sqrt{x-4}+4[/tex]
[tex]x-4=2\sqrt{x-4}[/tex]
Squaring both sides
[tex](x-4)^2=4(x-4)[/tex]
[tex]x^2+16-8x=4x-16[/tex]
[tex]x^2-12x+32=0[/tex]
[tex]x=\frac{12\pm \sqrt{12^2-4\times 32}}{2}[/tex]
[tex]x=\frac{12\pm 4}{2}[/tex]
[tex]x=4,8[/tex]
