Answer:
%[tex]S=66.7[/tex]%
Explanation:
Hello,
Sulfur monoxide, SO, has a molecular mass of 48g/mol (32g/mol for S and 16g/mol for O), thus, the present sulfur percent is given by the following equation as long as there's only one sulfur in the formula:
%[tex]S=\frac{1*32}{48}*100[/tex]%
%[tex]S=66.7[/tex]%
Best regards.
