if you mean solve for y to input into calculator 2y^2-x-8y+5=0 2y^2-8y=x-5 complete the square with y 2(y^2-4y)=x-5 2(y^2-4y+4-4)=x-5 2((y-2)^2-4)=x-5 2(y-2)^2-8=x-5 2(y-1)^2=x+3 (y-1)^2=(x+3)/2 y-1=√((x+3)/2) y=1+√((x+3)/2)
or we can graph it by hand (y-1)^2=(1/2)(x+3) it is a horizontal hyperbola get into (y-k)^2=4P(x-h) form (y-1)^2=4(1/8)(x-(-3)) since P>0, graph opens to right P is distance from directix to vertex and from vertex to focus
vertex is (-3,1) directix is x=-3.125 focus is (-2.875,1) READ FULL ANSWER AND ASK ME QUESTIONS BEFORE REPORTING
