Answer:
○ B) 624π mm.²
Step-by-step explanation:
[tex]\pi r(r + \sqrt{ {r}^{2} + {h}^{2}}) = S. A. \\ \\ \pi (12)(12 + \sqrt{{12}^{2} + {40}^{2}}) \\ \\ 12\pi(12 + \sqrt{1744}) = 12\pi(12 + 38) = 12\pi(50) = 600\pi \\ \\ 600\pi ≈ 624\pi[/tex]
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