Answer:
c=6.40 units
[tex]\implies \angle B=32\degree[/tex]
Step-by-step explanation:
The given triangle ABC is a right triangle;
According to the Pythagoras Theorem;
[tex]c^2=|AC|^2+|BC|^2[/tex]
We substitute AC=5 and BC=8
[tex]c^2=5^2+8^2[/tex]
[tex]c^2=25+16[/tex]
[tex]c^2=41[/tex]
[tex]c=\sqrt{41}[/tex]
c=6.40 to two decimal places.
In a right triangle the two acute angles add up to 90 degrees.
[tex]\angle B+58\degree=90\degree[/tex]
[tex]\implies \angle B=90\degree-58\degree[/tex]
[tex]\implies \angle B=32\degree[/tex]
