Respuesta :

dhiab

Answer:

Step-by-step explanation:

X²=12x-40

X²-12x+40=0

a=1  and b= -12 and c = 40

delta = b² - 4ac

delta = (-12)² - 4(1)(40) = 144 - 160 = - 16 = (4i)² ....i² = -1

x1= (12-4i)/2 =6-2i

x1= (12+4i)/2 =6+2i

devishri1977

Answer:

Step-by-step explanation:

x^2 = 12 x-40

x² - 12x + 40 = 0

a = 1;  b = -12; c = 40

4ac - b² = 4*1*40 - (-12)² = 160 - 144 = 16

x = -b ± √4ac-b² i / 2a

 = -(-12) ± √ 16 i

          2 * 1

= (12 ± 4 i )/ 2

= 2( 6 ±  2i)

        2

=   6 ±  2i

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