Answer: 0.3936
Step-by-step explanation:
Given: Mean : [tex]\mu =1387 \text{ grams}[/tex]
Standard deviation : [tex]\sigma = 161 \text{ grams}[/tex]
The formula to calculate z is given by :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x= 1,425 grams
[tex]z=\dfrac{1425-1387}{161}=0.23602484472\approx0.27[/tex]
The P Value =[tex]P(X>1425)=P(z>0.27)=1-0.6064198=0.3935802\approx0.3936[/tex]
Hence, the probability that a randomly selected broiler weighs more than 1,425 grams =0.3936
