For this case we have the following expression:
[tex]6+ \frac {4} {a} + \frac {b} {3}[/tex]
We must evaluate the expression when:
[tex]a = 4\\b = 3[/tex]
Substituting in the expression:
[tex]6+ \frac {4} {4} + \frac {3} {3} =\\6 + 1 + \frac {3} {3} =\\6 + 1 + 1 =\\7 + 1 =\\8[/tex]
ANswer:
The value of the expression when[tex]a = 4[/tex] and [tex]b = 3[/tex], is 8
