tyisheajohnson tyisheajohnson
  • 25-03-2019
  • Mathematics
contestada

5a - 24b =-15
10a + 45c =21
48b + 35c = 49

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5dwdvd 5dwdvd
  • 25-03-2019

5a + 15 = 24b so,

10a + 30 = 48b,

sub to third equation,

10a + 30 + 35c = 49

10a + 35c = 19

perform elimination with second equation

10a + 45c = 21

10a + 35c = 19

________________-

10c = 2

c = 1/5

sub to second equation,

10a + (45)(1/5) = 21

10a + 9 = 21

10a = 12

a = 6/5

sub to first equation

(5)(6/5) - 24b = -15

6 + 15 = 24b

21 = 24b

b = 7/8

redo the calculations, correct me if I'm wrong

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