Answer:
The area of the end of the rain gutter is [tex]20\ in^{2}[/tex]
Step-by-step explanation:
we know that
The area of a trapezoid is equal to
[tex]A=(1/2)(b1+b2)h[/tex]
In this problem we have
[tex]h=4\ in[/tex]
[tex]b1=4\ in[/tex]
[tex]b2=6\ in[/tex]
substitute
[tex]A=(1/2)(4+6)4=20\ in^{2}[/tex]
