Answer:
Option B. [tex]ln(60)=a[/tex]
Step-by-step explanation:
we have
[tex]e^{a}=60[/tex]
solve for a
Applying logarithm neperian (ln) both sides
[tex]ln(e^{a})=ln(60)[/tex]
[tex]a*ln(e)=ln(60)[/tex]
Remember that [tex]ln(e)=1[/tex]
so
[tex]a=ln(60)[/tex]
