Answer:
The derivative is [tex]\frac{\cos x - \sin x-1}{e^x}[/tex]
Step-by-step explanation:
[tex](\frac{\sin x+1}{e^x}+2)'=\frac{e^x\cos x-e^x(\sin x +1)}{e^{2x}}=\frac{\cos x - \sin x-1}{e^x}[/tex]
