Respuesta :

konrad509

[tex]3(x+4)\leq36\\\\3x+12\leq36\\\\3x\leq24\\\\x\leq8[/tex]

HI There!

Solve: 3(x + 4) <= 36

--------------------------------------------

Solution:

3(x + 4) ≤ 36

3x + 12 ≤ 36

3x + 12 − 12 ≤ 36 − 12

3x ≤ 24

3x/3 ≤ 24/3

x ≤ 8

--------------------------------------------

Answer: B). x ≤ 8

--------------------------------------------

Hope This Helps :)