Given:
2 moles HNO3
Required:
Grams of nitrogen
Solution:
3HNO2 -> HNO3 + 2NO + H2O
Moles of N2 = (2 moles HNO3)(2
moles NO /1 mole HNO3) = 4 Moles of NO
Molar mass of N2 = 28 g/mol
Mass of N2 = (4 Moles of NO)(1/2
mol N2/1 mol NO)( 28g/mol)
Mass of N2 = 56g H2O
