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A student travels from st. louis to indianapolis, a distance of 210 mi, in 7.0 h. the return trip over the same route takes 6.0 h. what is the average speed for

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Bouftou
The average speed for the student is equal to the total distance traveled divided by the total time it took to travel that distance.

(210mi+210mi)/(7h+6h) Simplify and you have your answer!
facundo3141592

Answer:

The average speed is equal to the total distance divided by the time

In the first travel, we have S1 = 210mi/7.0h = 30mi/h

In the second travel the time changes, and we have: S2 = 210mi/6h = 35mi/h

Now, the average speed in the total travel (going and returning) is:

St = (210mi + 210mi)/(7h + 6h) = 31.54mi/h

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