Simplify each of the following powers of i. i^99=

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21-09-2018
Mathematics

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Simplify each of the following powers of i. i^99=

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s1m1 s1m1 · Answer 1 · 2018-09-21T18:56:26+02:00

s1m1 s1m1

21-09-2018

i= sqrt (-1)

If the power is
- even then the value could be -1 or 1
-odd then the value could be -i or i

99 is odd so now is
-i if (99+1)/2 is even or is
i is (99+1)/2 is odd

Now check (99+1)/2= 100/2= 50,
50 is even so
i^99 = -i

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petersh1 petersh1 · Answer 2 · 2019-08-05T18:52:07+02:00

petersh1 petersh1

05-08-2019

Answer:

-i is the answer

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