Respuesta :

kenmyna
The  volume occupied    by 345.2 g of Cl2  at STP  is calculated as below

find the moles of Cl2  used

moles =mass/molar mass
molar mass of Cl2=35.5 x2= 71g/mol

moles= 345.2 g/ 71 g/mol =4.86 moles

at STP  1 mole= 22.4  liters
what about 4.86 moles

by cross  multiplication

4.86moles/1mole x22.4 liters =108.86 liters  of Cl2





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