dista610 dista610
  • 23-05-2018
  • Mathematics
contestada

square root 75 + square root 12

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TheBreeze
TheBreeze TheBreeze
  • 23-05-2018
Well first we should simplify:
[tex] \sqrt[5]{3} [/tex] + [tex] \sqrt[2]{3} [/tex]
This turns into:
[tex] \sqrt[7]{3}[/tex]
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sqdancefan
sqdancefan sqdancefan
  • 23-05-2018
[tex]\sqrt{75}+\sqrt{12}=\sqrt{5^{2}\cdot 3}+\sqrt{2^{2}\cdot 3}\\\\=5\sqrt{3}+2\sqrt{3}\\\\=7\sqrt{3}[/tex]
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