ChaudharyAkash469 ChaudharyAkash469
  • 23-11-2022
  • Mathematics
contestada

F(x)=\begin{cases}-2 & \text{ for }\hspace{10px} -6< x <-1\phantom{\frac{1}{1}} \\ -x-3 & \text{ for }\hspace{10px} -1< x <5\phantom{\frac{1}{1}}\end{cases} f(x)={ −2 −x−3 ​ for −6

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