suryanshumohansingh suryanshumohansingh 24-09-2022 Chemistry contestada From 230 mg of N204, x molecules are removed, 5 x 104 mole of N204 is left, then x will be (1) 2 × 10-3 (3) 4 × 10-3 (2) 1.2 × 1021 (4) 2.4 × 1021
